Monday, January 1, 2018

Solving Another Nonlinear Integer Fractional Programming Problem

Jsun Yui Wong

The computer program listed below seeks to solve the following nonlinear integer fractional programming problem:
   
Minimize    (-X(1) ^ 2 * X(2) ^ .5 + 2 * X(1) * X(2) ^ (-1) - X(2) ^ 2 + (2.8 * X(1) ^ (-1)) * X(2) + 7.5) / (X(1) * X(2) ^ 1.5 + 1) + (X(2) + .1) / (X(1) ^ 2 * X(2) ^ (-1) - 3 * X(1) ^ (-1) + 2 * X(1) * X(2) ^ 2 - 9 * X(2) ^ (-1) + 12)

subject to

         2 * X(1) ^ (-1)+ X(1) * X(2)<=4,

         X(1) + 3 * X(1) ^ (-1) * X(2)<=5

         X(1) ^ 2 - 3 * X(2) ^ 3<=2,

        1<=   X(1),  X(2) <=3,

 X(1) and X(2) are integer variables.

The problem above is based on Example 5 in Hou, Shen, and Wang [12], which is
   
Minimize    (-X(1) ^ 2 * X(2) ^ .5 + 2 * X(1) * X(2) ^ (-1) - X(2) ^ 2 + (2.8 * X(1) ^ (-1)) * X(2) + 7.5) / (X(1) * X(2) ^ 1.5 + 1) + (X(2) + .1) / (X(1) ^ 2 * X(2) ^ (-1) - 3 * X(1) ^ (-1) + 2 * X(1) * X(2) ^ 2 - 9 * X(2) ^ (-1) + 12)

subject to

         2 * X(1) ^ (-1)+ X(1) * X(2)<=4,

         X(1) + 3 * X(1) ^ (-1) * X(2)<=5

         X(1) ^ 2 - 3 * X(2) ^ 3<=2,

        1<=   X(1),  X(2) <=3.


X(3) through X(5) below are slack variables.


0 DEFDBL A-Z

2 DEFINT K

3 DIM B(99), N(99), A(99), H(99), L(99), U(99), X(1111), D(111), P(111), PS(33)
12 FOR JJJJ = -32000 TO 32000 STEP .01

    14 RANDOMIZE JJJJ
    16 M = -1D+37


    71 FOR J40 = 1 TO 2

        74 A(J40) = (1 + RND * 2)


    77 NEXT J40


    128 FOR I = 1 TO 100


        129 FOR KKQQ = 1 TO 2


            130 X(KKQQ) = A(KKQQ)
        131 NEXT KKQQ
        133 FOR IPP = 1 TO (1 + FIX(RND * 1))


            181 J = 1 + FIX(RND * 2)


            183 R = (1 - RND * 2) * A(J)
            187 X(J) = A(J) + (RND ^ (RND * 10)) * R
        222 NEXT IPP


        223 FOR J41 = 1 TO 2


            225 X(J41) = INT(X(J41))


        235 NEXT J41


        256 FOR J47 = 1 TO 2

            257 IF X(J47) < 1 THEN 1670
            258 IF X(J47) > 3 THEN 1670


        259 NEXT J47
        311 X(3) = 4 - 2 * X(1) ^ (-1) - X(1) * X(2)
        313 X(4) = 5 - X(1) - 3 * X(1) ^ (-1) * X(2)


        315 X(5) = 2 - X(1) ^ 2 + 3 * X(2) ^ 3


        322 FOR J44 = 3 TO 5


            325 IF X(J44) < 0 THEN X(J44) = X(J44) ELSE X(J44) = 0



        327 NEXT J44



        333 REM

        337 REM
        339 REM

        341 POBA = -(-X(1) ^ 2 * X(2) ^ .5 + 2 * X(1) * X(2) ^ (-1) - X(2) ^ 2 + (2.8 * X(1) ^ (-1)) * X(2) + 7.5) / (X(1) * X(2) ^ 1.5 + 1) - (X(2) + .1) / (X(1) ^ 2 * X(2) ^ (-1) - 3 * X(1) ^ (-1) + 2 * X(1) * X(2) ^ 2 - 9 * X(2) ^ (-1) + 12) + 1000000 * (X(3) + X(4) + X(5))


        466 P = POBA

        1111 IF P <= M THEN 1670


        1452 M = P
        1454 FOR KLX = 1 TO 5



            1455 A(KLX) = X(KLX)
        1456 NEXT KLX
        1557 REM GOTO 128

    1670 NEXT I
    1889 REM  IF M < -.000000000003 THEN 1999


    1900 PRINT A(1), A(2), A(3), A(4), A(5)

    1902 PRINT M, JJJJ

1999 NEXT JJJJ


This BASIC computer program was run with qb64v1000-win [36]. The complete output through JJJJ =    -31999.97000000001 is shown below:   

1    1    0     0    0
-5.516666666666667   -32000

1    1    0     0    0
-5.516666666666667   -31999.99

1    1    0     0    0
-5.516666666666667   -31999.98

2    1    0     0    0
-2.749122807017544   -31999.97000000001

Above there is no rounding by hand; it is just straight copying by hand from the monitor screen.  On a personal computer with a Pentium Dual-Core CPU E5200 @2.50GHz, 2.50 GHz, 960 MB of RAM and qb64v1000-win [36], the wall-clock time for obtaining the output through JJJJ= -31999.97000000001 was 2 seconds, not including the creating .EXE file time.  One can compare the computational results here with those in Table 2 of Hou, Shen, and Wang [12].   

Acknowledgment
I would like to acknowledge the encouragement of Roberta Clark and Tom Clark.

References

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