Tuesday, October 3, 2017

Solving a Signomial Nonlinear Integer/Discrete Programming Problem from the Literature

Jsun Yui Wong

The computer program listed below seeks to solve the following problem based on/modified from Example 5 on page 50 of Tsai and Lin [24].

Minimize         X(1) ^ 2 * X(2) ^ .816 * X(3) ^ 1.2 - X(1) ^ .8 - X(2) ^ .5 - X(3) ^ 1.2
 
subject to

      X(1) ^ .8 + X(2) ^ .9 + X(3) ^ .5>=16

      X(1) ^ -1.5 + X(2) ^ 1.7+ X(3) ^ 1.2<=500

where X(1), X(2), X(3) Epsilon { 1.1, 1.2, 1.3,..., 52.0}.
     
X(1), X(2), and X(3) are discrete variables.

The added variables X(4) and X(5) below are slack variables.  One takes note of line 330, which is 330 IF X(J99) < 0 THEN X(J99) = X(J99) ELSE X(J99) = 0.


0 DEFDBL A-Z

2 DEFINT K

3 DIM B(99), N(99), A(99), H(99), L(99), U(99), X(1111), D(111), P(111), PS(33)
12 FOR JJJJ = -32000 TO 32000 STEP .01

    14 RANDOMIZE JJJJ
    16 M = -1D+37
    71 FOR J44 = 1 TO 3

        75 A(J44) = 1.1 + (INT(RND * 510)) * .1
    79 NEXT J44


    128 FOR I = 1 TO 50


        129 FOR KKQQ = 1 TO 3
            130 X(KKQQ) = A(KKQQ)
        131 NEXT KKQQ
        133 FOR IPP = 1 TO (1 + FIX(RND * 2))

            181 J = 1 + FIX(RND * 3)
            182 X(J) = 1.1 + (INT(RND * 510)) * .1
            183 REM r = (1 - RND * 2) * A(J)
            187 REM X(J) = A(J) + (RND ^ (RND * 10)) * r

        191 NEXT IPP

        211 IF X(1) < 1.1 THEN 1670

        212 IF X(1) > 52 THEN 1670

        213 IF X(2) < 1.1 THEN 1670

        214 IF X(2) > 52 THEN 1670

        215 IF X(3) < 1.1 THEN 1670

        216 IF X(3) > 52 THEN 1670


        301 X(4) = -16 + X(1) ^ .8 + X(2) ^ .9 + X(3) ^ .5

        303 X(5) = 500 - X(1) ^ -1.5 - X(2) ^ 1.7 - X(3) ^ 1.2

        325 FOR J99 = 4 TO 5


            330 IF X(J99) < 0 THEN X(J99) = X(J99) ELSE X(J99) = 0


        331 NEXT J99


        357 POBA = -X(1) ^ 2 * X(2) ^ .816 * X(3) ^ 1.2 + X(1) ^ .8 + X(2) ^ .5 + X(3) ^ 1.2 + 1000000 * (X(4) + X(5))


        466 P = POBA

        1111 IF P <= M THEN 1670


        1452 M = P
        1454 FOR KLX = 1 TO 5


            1459 A(KLX) = X(KLX)
        1460 NEXT KLX
        1557 GOTO 128

    1670 NEXT I

    1889 IF M < -8.33 THEN 1999
    1900 PRINT A(1), A(2), A(3), A(4)
    1901 PRINT A(5), M, JJJJ
1999 NEXT JJJJ


This BASIC computer program was run with qb64v1000-win [25].  The complete output through JJJJ =-31974.60000000407
is shown below:

1.1        18.6       1.1       0
0         -8.222813024242807          -31988.67000000181

1.1        18.6       1.1       0
0         -8.222813024242807          -31981.340000003

1.1        18.7       1.1       0
0         -8.275851373759423          -31974.60000000407

Above there is no rounding by hand; it is just straight copying by hand from the monitor screen. 

On a personal computer with a Pentium Dual-Core CPU E5200 @2.50GHz, 2.50 GHz, 960 MB of RAM and qb64v1000-win [25], the wall-clock time for obtaining the output through JJJJ=-31974.60000000407 was 10 seconds--most of these seconds were for creating the .EXE file.

Acknowledgment

I would like to acknowledge the encouragement of Roberta Clark and Tom Clark.

References

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[25] Wikipedia, QB64, https://en.wikipedia.org/wiki/QB64.     

[26] Jsun Yui Wong (2012, April 12).  The Domino Method of General Integer Nonlinear Programming Applied to a Nonlinear Fractional Programming Problem from the Literature. http://myblogsubstance.typepad.com/substance/2012/04/12/ 

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