Wednesday, November 8, 2017

Solving in Integers a Fractional Nonlinear Integer Programming Problem

Jsun Yui Wong

The computer program listed below seeks to solve the following integer problem:

Minimize 

(2 + X(5)) / (X(1) * X(2) * (2 * X(3) + X(4))) - X(5) ^ .5 * X(3) ^ 1.5 + 2 * X(2) + X(4)  - (((X(3) + 2) * X(1) * X(2) ^ 2) / (200 * (2 ^ .5) * X(1) + 100 * X(2)))

subject to

        8 / (X(1) * (X(2) + 3 * X(4)) ^ 2) + 1 / (X(5) ^ 3)<=2,

        - 2 * X(1) + X(3) - X(4)<=10,

         X(1) + X(3) + .5 * X(5)<=8,

         X(1) ^ 3 + X(2) ^ 3 + X(3) ^ 3 + X(4) ^ 3 + X(5) ^ 3<=200,

         .1 <= X(i) <= 10, i=1, 2, 3, 4, 5,

X(1) through X(5) are integer variables.

The integer problem above is based mainly on Example 3 in Tsai [24, p. 408].

X(6) through X(9) below are slack variables.


0 DEFDBL A-Z

2 DEFINT K

3 DIM B(99), N(99), A(99), H(99), L(99), U(99), X(1111), D(111), P(111), PS(33)
12 FOR JJJJ = -32000 TO 32000 STEP .01

    14 RANDOMIZE JJJJ
    16 M = -1D+37
    70 FOR J44 = 1 TO 5

        72 A(J44) = .1 + RND * 9.9



    73 NEXT J44



    128 FOR I = 1 TO 1000



        129 FOR KKQQ = 1 TO 5

            130 X(KKQQ) = A(KKQQ)
        131 NEXT KKQQ
        133 FOR IPP = 1 TO (1 + FIX(RND * 4))



            181 J = 1 + FIX(RND * 5)

            183 r = (1 - RND * 2) * A(J)
            187 X(J) = A(J) + (RND ^ (RND * 10)) * r

        191 NEXT IPP

        196 FOR J99 = 1 TO 5

            199 X(J99) = INT(X(J99))

            201 IF X(J99) < .1 THEN 1670
            203 IF X(J99) > 10 THEN 1670
        204 NEXT J99

        305 X(6) = 2 - 8 / (X(1) * (X(2) + 3 * X(4)) ^ 2) - 1 / (X(5) ^ 3)



        306 X(7) = 10 + 2 * X(1) - X(3) + X(4)



        307 X(8) = 8 - X(1) - X(3) - .5 * X(5)

        311 X(9) = 200 - X(1) ^ 3 - X(2) ^ 3 - X(3) ^ 3 - X(4) ^ 3 - X(5) ^ 3

        325 FOR J99 = 6 TO 9

            327 XX(J99) = X(J99)



            330 IF X(J99) < 0 THEN X(J99) = X(J99) ELSE X(J99) = 0

        331 NEXT J99



        357 POBA = -(2 + X(5)) / (X(1) * X(2) * (2 * X(3) + X(4))) + X(5) ^ .5 * X(3) ^ 1.5 - 2 * X(2) - X(4) + 1000000 * (X(6) + X(7) + X(8) + X(9)) + (((X(3) + 2) * X(1) * X(2) ^ 2) / (200 * (2 ^ .5) * X(1) + 100 * X(2)))



        466 P = POBA

        1111 IF P <= M THEN 1670



        1452 M = P
        1454 FOR KLX = 1 TO 9



            1456 XXX(KLX) = XX(KLX)

            1459 A(KLX) = X(KLX)
        1460 NEXT KLX
        1557 GOTO 128

    1670 NEXT I



    1889 IF M < 10 THEN 1999

    1900 PRINT A(1), A(2), A(3), A(4), A(5)

    1902 PRINT A(6), A(7), A(8), X(9)

    1903 PRINT XXX(6), XXX(7), XXX(8), XXX(9)

    1912 PRINT M, JJJJ

1999 NEXT JJJJ


This BASIC computer program was run with qb64v1000-win [28]. The complete output through JJJJ =-31999.82000000003 is  shown below:

1   1   5   1   4
0   0   0   0   0
1.484375   8   0   8
18.83350950079081      -31999.96000000001

1   1   5   1   4
0   0   0   0   0
1.484375   8   0   8
18.83350950079081      -31999.93000000001

1   1   5   1   4
0   0   0   0   0
1.484375   8   0   8
18.83350950079081      -31999.83000000003

2   1   5   1   2
0   0   0   0   0
1.625   10   0   57
12.65060107369884      -31999.82000000003

Above there is no rounding by hand; it is just straight copying by hand from the monitor screen.

On a personal computer with a Pentium Dual-Core CPU E5200 @2.50GHz, 2.50 GHz, 960 MB of RAM and qb64v1000-win [28], the wall-clock time for obtaining the output through JJJJ=-31999.82000000003 was 2 seconds, not including the time for creating the .EXE file.   
   
Acknowledgment

I would like to acknowledge the encouragement of Roberta Clark and Tom Clark.

References

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