Friday, November 3, 2017

Solving a Nonlinear Programming Problem Involving Noncovex Posynomial and Signomial Terms

Jsun Yui Wong

The computer program listed below seeks to solve the following nonlinear programming formulation from page 452 of Lu [14]: 

Minimize            .622 * X(1) * X(3) * X(4) + 1.7781 * X(2) * X(3) ^ 2 + 3.1661 * X(1) ^ 2 * X(4) + 19.84 * X(1) ^ 2 * X(3)

subject to

        -X(1)+ .0193 * X(3)<=0,

        - X(2) + .00954 * X(3)<=0,

        1296000 - 3.141592654 * X(3) ^ 2 * X(4) - (4 / 3) * 3.141592654 * X(3) ^ 3<=0,

        - 240+ X(2)<=0,

          .0625<=X(i) <= 6.1875, i=1, 2,

           10<=X(3) <= 200, i=3, 4.

X(1) through X(4) are continuous.

X(5) through X(8) below are slack variables.


0 DEFDBL A-Z

2 DEFINT K

3 DIM B(199), N(199), A(199), H(199), L(199), U(199), X(1111), D(111), P(111), PS(133)

12 FOR JJJJ = -32000 TO 32000 STEP .01

    14 RANDOMIZE JJJJ
    16 M = -1D+37

    22 FOR J55 = 1 TO 2


        67 A(J55) = .0625 + RND * 6.125


    71 NEXT J55
    82 FOR J55 = 3 TO 4


        86 A(J55) = 10 + RND * 190


    88 NEXT J55


    128 FOR I = 1 TO 60000


        129 FOR KKQQ = 1 TO 4


            130 X(KKQQ) = A(KKQQ)
        131 NEXT KKQQ

        132 REM GOTO 163

        133 FOR IPP = 1 TO (1 + FIX(RND * 4))


            151 J = 1 + FIX(RND * 4)

            153 r = (1 - RND * 2) * A(J)
            157 X(J) = A(J) + (RND ^ (RND * 10)) * r


        161 NEXT IPP
        163 REM

        164 REM


        197 IF X(1) < .0625 THEN 1670

        199 IF X(1) > 6.1875 THEN 1670

        201 IF X(2) < .0625 THEN 1670

        203 IF X(2) > 6.1875 THEN 1670

        205 IF X(3) < 10 THEN 1670

        207 IF X(3) > 200 THEN 1670

        209 IF X(4) < 10 THEN 1670

        211 IF X(4) > 200 THEN 1670


        261 X(5) = X(1) - .0193 * X(3)

        264 X(6) = X(2) - .00954 * X(3)

        267 X(7) = -1296000 + 3.141592654 * X(3) ^ 2 * X(4) + (4 / 3) * 3.141592654 * X(3) ^ 3

        269 X(8) = 240 - X(2)
        281 FOR J99 = 5 TO 8

            283 IF X(J99) < 0 THEN X(J99) = X(J99) ELSE X(J99) = 0


        285 NEXT J99

        365 POBA = -.622 * X(1) * X(3) * X(4) - 1.7781 * X(2) * X(3) ^ 2 - 3.1661 * X(1) ^ 2 * X(4) - 19.84 * X(1) ^ 2 * X(3) + 1000000 * (X(8) + X(7) + X(6) + X(5))

        466 P = POBA

        1111 IF P <= M THEN 1670


        1452 M = P
        1454 FOR KLX = 1 TO 8



            1459 A(KLX) = X(KLX)
        1460 NEXT KLX
        1557 REM GOTO 128

    1670 NEXT I


    1889 IF M < -5884.5 THEN 1999


    1900 PRINT A(1), A(2), A(3), A(4), A(5)

    1911 PRINT A(6), A(7), A(8), M, JJJJ

1999 NEXT JJJJ


This BASIC computer program was run with qb64v1000-win [27]. The complete output through JJJJ = -31951.60000000775 is  shown below:

.7791371869593762        .3851279152120704         40.36980243312682
199.3025835450308           0
0       0       0       -5884.48288302348
-31993.1700000011

.7785102423305716        .38481801615722         40.33731825546528
199.7537562076116          0
0       0       0       -5883.4077896634
-31951.60000000775

Above there is no rounding by hand; it is just straight copying by hand from the monitor screen.  The computational results above can be compared with the results in Table 7 of Lu [14, p.  453].

On a personal computer with a Pentium Dual-Core CPU E5200 @2.50GHz, 2.50 GHz, 960 MB of RAM and qb64v1000-win [27], the wall-clock time for obtaining the output through
JJJJ=  -31951.60000000775 was 10 minutes, total.   
   
Acknowledgment

I would like to acknowledge the encouragement of Roberta Clark and Tom Clark.

References

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