Monday, July 2, 2018

Fractional Mixed-Integer Nonlinear Programming Applied to a Reliability-Redundancy Problem, Corrected Edition

Jsun Yui Wong

The computer program listed below seeks to solve the following fractional mixed-integer nonlinear programming problem, a return-on-investment problem, which is based on the reliability/cost ratio problem on pp. 496-497 of Liu [277]; one notes Table 7:

         
Maximize                         ((1 - (1 - X(5)) ^ X(1)) * (1 - (1 - X(6)) ^ X(2)) * (1 - (1 - X(7)) ^ X(3)) * (1 - (1 - X(8)) ^ X(4)))   /   ((1 / 10 ^ 5) * (-1000 / LOG(X(5))) ^ 1.5 * (X(1) + EXP(X(1) / 4)) + (2.3 / 10 ^ 5) * (-1000 / LOG(X(6))) ^ 1.5 * (X(2) + EXP(X(2) / 4)) + (.3 / 10 ^ 5) * (-1000 / LOG(X(7))) ^ 1.5 * (X(3) + EXP(X(3) / 4)) + (2.3 / 10 ^ 5) * (-1000 / LOG(X(8))) ^ 1.5 * (X(4) + EXP(X(4) / 4)))

subject to

            1 * X(1) ^ 2 + 2 * X(2) ^ 2 + 3 * X(3) ^ 2 + 2 * X(4) ^ 2<=250


              6 * X(1) * EXP(X(1) / 4) + (6) * X(2) * EXP(X(2) / 4) + (8) * X(3) * EXP(X(3) / 4) + (7) * X(4) * EXP(X(4) / 4)<=500


         (1 / 10 ^ 5) * (-1000 / LOG(X(5))) ^ 1.5 * (X(1) + EXP(X(1) / 4)) + (2.3 / 10 ^ 5) * (-1000 / LOG(X(6))) ^ 1.5 * (X(2) + EXP(X(2) / 4))
+ (.3 / 10 ^ 5) * (-1000 / LOG(X(7))) ^ 1.5 * (X(3) + EXP(X(3) / 4)) + (2.3 / 10 ^ 5) * (-1000 / LOG(X(8))) ^ 1.5 * (X(4) + EXP(X(4) / 4))<=400

            1<= X(i) <= 10, i=1, 2, 3, 4; X(1) through X(4) are integer variables

.5<= X(5), X(6), X(7), X(8)<=.999999.

X(9), X(10), and X(11) below are slack variables added. 

Whereas line 128 of the earlier edition is 155 REM IF j > 4.5 THEN GOTO 156 ELSE GOTO 164, here line 128 is 155  IF j > 4.5 THEN GOTO 156 ELSE GOTO 164.  This is the correction.




0 DEFDBL A-Z

1 DEFINT K

2 DIM B(99), N(99), A(2002), H(99), L(99), U(99), X(2002), D(111), P(111), PS(33), J44(2002), J(99), AA(99), HR(32), HHR(32), LHS(44), PLHS(44), LB(22), UB(22), PX(22), CC(20), RR(20), WW(20)

81 FOR JJJJ = -32000 TO 32000


    89 RANDOMIZE JJJJ
    90 M = -3E+30

    95 FOR J44 = 1 TO 4

        97 A(J44) = FIX(1 + RND * 10)

    99 NEXT J44

    115 FOR J44 = 5 TO 8

        117 A(J44) = .5 + RND * .499999

    119 NEXT J44

    128 FOR I = 1 TO 10000

        129 FOR KKQQ = 1 TO 8
            130 X(KKQQ) = A(KKQQ)
        131 NEXT KKQQ
        151 FOR IPP = 1 TO FIX(1 + RND * 3)

            153 j = 1 + FIX(RND * 8)
            154 REM GOTO 164
            155 IF j > 4.5 THEN GOTO 156 ELSE GOTO 164 

            156 r = (1 - RND * 2) * A(j)
            158 X(j) = A(j) + (RND ^ (RND * 10)) * r

            161 GOTO 169


            164 IF RND < .5 THEN X(j) = A(j) - 1 ELSE X(j) = A(j) + 1


        169 NEXT IPP
        326 FOR J44 = 1 TO 4

            327 X(J44) = INT(X(J44))

            328 IF X(J44) < 1 THEN 1670

            329 IF X(J44) > 10 THEN 1670
        331 NEXT J44

        336 FOR J44 = 5 TO 8


            338 IF X(J44) < .5## THEN 1670

            339 IF X(J44) > .999999## THEN 1670
        340 NEXT J44


        341 X(9) = 250 - 1 * X(1) ^ 2 - 2 * X(2) ^ 2 - 3 * X(3) ^ 2 - 2 * X(4) ^ 2


        343 X(10) = 500 - 6 * X(1) * EXP(X(1) / 4) - (6) * X(2) * EXP(X(2) / 4) - (8) * X(3) * EXP(X(3) / 4) - (7) * X(4) * EXP(X(4) / 4)


        346 X(11) = 400 - (1 / 10 ^ 5) * (-1000 / LOG(X(5))) ^ 1.5 * (X(1) + EXP(X(1) / 4)) - (2.3 / 10 ^ 5) * (-1000 / LOG(X(6))) ^ 1.5 * (X(2) + EXP(X(2) / 4)) - (.3 / 10 ^ 5) * (-1000 / LOG(X(7))) ^ 1.5 * (X(3) + EXP(X(3) / 4)) - (2.3 / 10 ^ 5) * (-1000 / LOG(X(8))) ^ 1.5 * (X(4) + EXP(X(4) / 4))


        355 FOR J44 = 9 TO 11


            357 IF X(J44) < 0 THEN X(J44) = X(J44) ELSE X(J44) = 0

        359 NEXT J44


        398 PDU = ((1 - (1 - X(5)) ^ X(1)) * (1 - (1 - X(6)) ^ X(2)) * (1 - (1 - X(7)) ^ X(3)) * (1 - (1 - X(8)) ^ X(4))) / ((1 / 10 ^ 5) * (-1000 / LOG(X(5))) ^ 1.5 * (X(1) + EXP(X(1) / 4)) + (2.3 / 10 ^ 5) * (-1000 / LOG(X(6))) ^ 1.5 * (X(2) + EXP(X(2) / 4)) + (.3 / 10 ^ 5) * (-1000 / LOG(X(7))) ^ 1.5 * (X(3) + EXP(X(3) / 4)) + (2.3 / 10 ^ 5) * (-1000 / LOG(X(8))) ^ 1.5 * (X(4) + EXP(X(4) / 4))) + 1000000 * (X(9) + X(10) + X(11))


        466 P = PDU
        1111 IF P <= M THEN 1670
        1452 M = P
        1454 FOR KLX = 1 TO 11

            1455 A(KLX) = X(KLX)
        1456 NEXT KLX


        1557 GOTO 128
    1670 NEXT I
    1889 REM IF M < -999999 THEN 1999



    1904 PRINT A(1), A(2), A(3)
    1905 PRINT A(4), A(5), A(6)
    1906 PRINT A(7), A(8), A(9)
    1907 PRINT A(10), A(11)

    1909 PRINT M, JJJJ

1999 NEXT JJJJ

This BASIC computer program was run with QB64v1000-win [40].  The output through JJJJ= -31998 is summarized below:

.4          3           5
3          .5000000000000607                                      .5000000000000027
.5000000000000038                        .5000000000000134                 0
0          0
.0386826290706846                -32000 

4           3           5
3          .5000000000000003                                      .5000000000000012
.5000000000000363                        .5000000000000001                 0
0          0
3.868262907068577D-02                -31999 

4           3           5
3          .5000000000000112                                      .50000000000044 
.5000000000000007                        .5000000000000022                 0
0          0
.0386826290706738                -31998 

Above there is no rounding by hand; it is just straight copying by hand from the monitor screen. On a personal computer with a Pentium Dual-Core CPU E5200 @2.50GHz, 2.50 GHz, 960 MB of RAM and QB64v1000-win [40], the wall-clock time (not CPU time) for obtaining the output through JJJJ = -31998 was 4 seconds, not including the time for “Creating .EXE file” (13 seconds, total, including the time for “Creating .EXE file” ). 


Acknowledgment

I would like to acknowledge the encouragement of Roberta Clark and Tom Clark.

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[43] Jsun Yui Wong (2011, July 23).  A General Nonlinear Integer/Discrete/Continuous Programming Solver Applied to Three Instances of the Haverly Pooling Problem.  Retrieved from http://myblogsubstance.typepad.com/substance/2011/07/

[44] Jsun Yui Wong (2011 July 27).   A General Nonlinear Integer/Discrete/Continuous Programming Solver Applied to an Alkylation-Process Model, Sixth Edition.  Retrieved from http://computationalresultsfromcomputerprograms.wordpress.com/2011/07/27/

[45] Jsun Yui Wong (2012, April 24).  The Domino Method of General Integer Nonlinear Programming  Applied to Problem 10 of Lawler and Bell.  Retrieved from http://computationalresultsfromcomputerprograms.wordpress.com/2012/4/24/

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[47]  Jsun Yui Wong (2013 January 10).  The Domino Method of General Integer Nonlinear Programming Applied to Alkylation Process Optimization.  http://myblogsubstance.typepad.com/substance/2013/01/



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