Saturday, July 28, 2018

This Mixed-Integer Nonlinear Programming Solver Applied to a Complex (Bridge) Reliability-Redundancy Allocation Problem

Jsun Yui Wong

The computer program listed below seeks to solve the following problem based on Chen [10, p. 1562, P3, Complex (Bridge) System] and on Liu and Qin [30, p. 2053, Problem 2, Complex (Bridge) System]:           

Maximize        O(1) * O(2) + O(3) * O(4) + O(1) * O(4) * O(5) + O(2) * O(3) * O(5) - O(1) * O(2) * O(3) * O(4) - O(1) * O(2) * O(3) * O(5) - O(1) * O(2) * O(4) * O(5) - O(1) * O(3) * O(4) * O(5) - O(2) * O(3) * O(4) * O(5) + 2 * O(1) * O(2) * O(3) * O(4) * O(5)

 where O(J44) = 1 - ((1 - (X(J44 + 5)))) ^ X(J44)--see line 391 through line 394 below

subject to

        1 * X(1) ^ 2 + 2 * X(2) ^ 2 + 3 * X(3) ^ 2 + 4 * X(4) ^ 2 + 2 * X(5) ^ 2<=110

         (2.33 / 10 ^ 5) * ((-1000 / LOG(X(6))) ^ 1.5) * (X(1) + EXP(X(1) / 4)) + (1.45 / 10 ^ 5) * ((-1000 / LOG(X(7))) ^ 1.5) * (X(2) + EXP(X(2) / 4)) + (.541 / 10 ^ 5) * ((-1000 / LOG(X(8))) ^ 1.5) * (X(3) + EXP(X(3) / 4)) + (8.05 / 10 ^ 5) * ((-1000 / LOG(X(9))) ^ 1.5) * (X(4) + EXP(X(4) / 4)) + (1.95 / 10 ^ 5) * ((-1000 / LOG(X(10))) ^ 1.5) * (X(5) + EXP(X(5) / 4))<=175

         7 * X(1) * EXP(X(1) / 4) + (8) * X(2) * EXP(X(2) / 4) + (8) * X(3) * EXP(X(3) / 4) + (6) * X(4) * EXP(X(4) / 4) + (9) * X(5) * EXP(X(5) / 4)<=200

            .5<= X(i) <= 1, 6<=i<=10

where X(1) through X(5) are positive general integer variables with X(i)=1, 2, 3, ..., 10.
       
X(11) through X(13) below are slack variables added.


0 DEFDBL A-Z

1 DEFINT K

2 DIM B(99), N(99), A(2002), H(99), L(99), U(99), X(2002), D(111), P(111), PS(33), J44(2002), J(99), AA(99), HR(32), HHR(32), LHS(44), PLHS(44), LB(22), UB(22), PX(22), CC(20), RR(20), WW(20)

81 FOR JJJJ = -32000 TO 32000


    89 RANDOMIZE JJJJ
    90 M = -3E+30

    95 FOR J44 = 1 TO 5

        97 A(J44) = FIX(1 + RND * 10)

    99 NEXT J44

    115 FOR J44 = 6 TO 10

        117 A(J44) = .5 + RND * .49999

    119 NEXT J44

    128 FOR I = 1 TO 100000


        129 FOR KKQQ = 1 TO 10
            130 X(KKQQ) = A(KKQQ)
        131 NEXT KKQQ
        151 FOR IPP = 1 TO FIX(1 + RND * 3)


            153 j = 1 + FIX(RND * 10)


            155 IF j > 5.5 THEN GOTO 156 ELSE GOTO 164

            156 r = (1 - RND * 2) * A(j)
            158 X(j) = A(j) +  (RND ^ (RND * 10)) * r


            161 GOTO 169


            164 IF RND < .5 THEN X(j) = A(j) - 1 ELSE X(j) = A(j) + 1


        169 NEXT IPP
        326 FOR J44 = 1 TO 5

            327 X(J44) = CINT(X(J44))



            328 IF X(J44) < 1 THEN 1670

            329 IF X(J44) > 10 THEN 1670
        331 NEXT J44

        336 FOR J44 = 6 TO 10


            338 IF X(J44) < .5## THEN 1670

            339 IF X(J44) > .999999## THEN 1670
        340 NEXT J44


        341 X(11) = 110 - 1 * X(1) ^ 2 - 2 * X(2) ^ 2 - 3 * X(3) ^ 2 - 4 * X(4) ^ 2 - 2 * X(5) ^ 2



        343 X(12) = 200 - 7 * X(1) * EXP(X(1) / 4) - (8) * X(2) * EXP(X(2) / 4) - (8) * X(3) * EXP(X(3) / 4) - (6) * X(4) * EXP(X(4) / 4) - (9) * X(5) * EXP(X(5) / 4)


        346 X(13) = 175 - (2.33 / 10 ^ 5) * ((-1000 / LOG(X(6))) ^ 1.5) * (X(1) + EXP(X(1) / 4)) - (1.45 / 10 ^ 5) * ((-1000 / LOG(X(7))) ^ 1.5) * (X(2) + EXP(X(2) / 4)) - (.541 / 10 ^ 5) * ((-1000 / LOG(X(8))) ^ 1.5) * (X(3) + EXP(X(3) / 4)) - (8.05 / 10 ^ 5) * ((-1000 / LOG(X(9))) ^ 1.5) * (X(4) + EXP(X(4) / 4)) - (1.95 / 10 ^ 5) * ((-1000 / LOG(X(10))) ^ 1.5) * (X(5) + EXP(X(5) / 4))



        355 FOR J44 = 11 TO 13


            357 IF X(J44) < 0 THEN X(J44) = X(J44) ELSE X(J44) = 0


        359 NEXT J44



        391 FOR J44 = 1 TO 5

            393 O(J44) = 1 - ((1 - (X(J44 + 5)))) ^ X(J44)

        394 NEXT J44



        401 PDU = O(1) * O(2) + O(3) * O(4) + O(1) * O(4) * O(5) + O(2) * O(3) * O(5) - O(1) * O(2) * O(3) * O(4) - O(1) * O(2) * O(3) * O(5) - O(1) * O(2) * O(4) * O(5) - O(1) * O(3) * O(4) * O(5) - O(2) * O(3) * O(4) * O(5) + 2 * O(1) * O(2) * O(3) * O(4) * O(5) + 1000000 * (X(11) + X(12) + X(13))



        466 P = PDU
        1111 IF P <= M THEN 1670
        1452 M = P
        1454 FOR KLX = 1 TO 13

            1455 A(KLX) = X(KLX)
        1456 NEXT KLX


        1557 GOTO 128
    1670 NEXT I
    1889 IF M < .99988961 THEN 1999   


    1904 PRINT A(1), A(2), A(3)
    1905 PRINT A(4), A(5), A(6)
    1906 PRINT A(7), A(8), A(9)
    1907 PRINT A(10), A(11), A(12), A(13)

    1909 PRINT M, JJJJ

1999 NEXT JJJJ


This BASIC computer program was run with QB64v1000-win [45].  The complete output of a single run through JJJJ= -31917 is shown below:

3     3     2
4     1                           .8271828129627745
.8584470687531135      .9146456241665405   .6473915423816696
.7083633509542693
.9998896175115296      -31982

3     3     2
4     1                          .8275566506233765
.8585263665874964      .914785253366289    .6470983072525923
.7044017880815086
.9998896208547377      -31917

Above there is no rounding by hand; it is just straight copying by hand from the monitor screen. On a personal computer with a Pentium Dual-Core CPU E5200 @2.50GHz, 2.50 GHz, 960 MB of RAM and QB64v1000-win [45], the wall-clock time (not CPU time) for obtaining the output through JJJJ = -31917 was 5 minutes, total, including the time for “Creating .EXE file."  One can compare the computational results above with those in Chen [10, p. 1565, Table 6] and in Liu and Qin [30, p. 2054, Table VIII].           
       

Acknowledgment

I would like to acknowledge the encouragement of Roberta Clark and Tom Clark.

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